我的BSOOC里需要一个查询表主键外键信息的SQL，昨晚研究到凌晨1点，终于能实现这个目标：Oracle:select o.obj# as objectId, o.name AS tableName, oc.name AS constraintName, decode(c.type#, 1, 'C', 2, 'P', 3, 'U', 4, 'R', 5, 'V', 6, 'O', 7,'C', '?') as constraintType, col.name AS columnName from sys.con$ oc, sys.con$ rc, sys.obj$ ro,sys.obj$ o, sys.obj$ oi, sys.cdef$ c, sys.col$ col, sys.ccol$ cc, sys.attrcol$ acwhere oc.con# = c.con# and c.obj# = o.obj# and c.rcon# = rc.con#(+) and c.enabled = oi.obj#(+) and c.robj# = ro.obj#(+) and c.type# != 8 and c.type# != 12;;;;/* don't include log groups */ and c.con# = cc.con# and cc.obj# = col.obj# and cc.intcol# = col.intcol# and cc.obj# = o.obj# and col.obj# = ac.obj#(+) and col.intcol# = ac.intcol#(+) and o.name = 'your table'SQL Server:
SELECT sysobjects.id objectId,OBJECT_NAME(sysobjects.parent_obj) tableName,sysobjects.name constraintName, sysobjects.xtype AS constraintType,syscolumns.name AS columnNameFROM sysobjects INNER JOIN sysconstraintsON sysobjects.xtype in('C', 'F', 'PK', 'UQ', 'D') AND sysobjects.id = sysconstraints.constidLEFT OUTER JOIN syscolumns ON sysconstraints.id = syscolumns.idWHERE OBJECT_NAME(sysobjects.parent_obj)='your table'其它数据库还没时间去实现.
